Quiz 5.2:


Question:

The US census projects the population of the state of Washington using the function \( N(t)=6.72e^{0.026t} \) where \( N(t) \) is in millions and \( t \) is in years since 2012.
a) What is the population's continuous growth rate?
b) What is the population of Washington in year \( t = 0 \)
c) How many years before the population triples?
d) In what year does the model predict a population of 1? Is this reasonable?


4th Ed: #50
5th Ed: #49


Solution:

a) 2.6%
b) 6.72 million
c)
\( 3(6.72)=6.72e^{0.026t} \)
\( 3 = e^{0.026t} \)
\( \ln 3 = 0.026t \)
\( t = \frac{ln 3}{0.026} \approx 42 \) years
d)
\( \frac{1}{1000000}=6.72e^{0.026t} \)
\( \frac{1}{6720000} = e^{0.026t} \)
\( \ln \frac{1}{6720000} = 0.026t \)
\( t = \frac{\ln \frac{1}{6720000}}{0.026} \approx -605 \) years
So in year 2012-605=1407. This is not reasonable because the US did not even exist yet, let alone Washington state.
JCCC
JCCC