Quiz 4.5:

Question:

A quantity \(Q\) has initial quantity \(Q_0=500\) and a decay rate of 7% per unit time.
a) Give a formula for \( Q(t) \) for noncontinuous decay rate
b) Give a formula for \(Q(t)\) for a continuous decay rate
c) Find the quantity in each case at \(t=10\)


4th Ed: #22
5th Ed: #17

Solution:

a) \(Q_n(t)=500(0.93)^t \)
b) \(Q_c(t)=500e^{-0.07t} \)
c) \(Q_n(10)= 500(0.93)^{10} \approx 241.99\) and \(Q_c(10)=500e^{-0.07(10)} \approx 248.29\)
JCCC
JCCC