Quiz 2.1:
Question:
Let \( v=f(t) \) be the speed of a braking car, in feet per second, \( t \) seconds after the brakes are applied.
a) If \( t=1 \), what is \( f(t+5) \)?
b) If \( t=1 \), what is \( f(t)+5 \)?
c) Solve \( f(t+2) = 40 \) fot \(t\).
a) If \( t=1 \), what is \( f(t+5) \)?
b) If \( t=1 \), what is \( f(t)+5 \)?
c) Solve \( f(t+2) = 40 \) fot \(t\).
Solution:
a) \( f(1+5)=f(6) \approx 5 \)
b) \( f(1)+5 \approx 68 + 5 = 73 \)
c) \( f(t=2)=40 \)
a) \( f(1+5)=f(6) \approx 5 \)
b) \( f(1)+5 \approx 68 + 5 = 73 \)
c) \( f(t=2)=40 \)
\( t+2 \approx 1.75 \)
\( t \approx -0.25 \)
\( t \approx -0.25 \)
